Optimal. Leaf size=129 \[ \frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}+\frac{5 A b \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{2 a^{7/2}}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}+\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}} \]
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Rubi [A] time = 0.11944, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {823, 835, 807, 266, 63, 208} \[ \frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}+\frac{5 A b \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{2 a^{7/2}}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}+\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 823
Rule 835
Rule 807
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{A+B x}{x^3 \left (a+b x^2\right )^{5/2}} \, dx &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}-\frac{\int \frac{-5 a A b-4 a b B x}{x^3 \left (a+b x^2\right )^{3/2}} \, dx}{3 a^2 b}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}+\frac{\int \frac{15 a^2 A b^2+8 a^2 b^2 B x}{x^3 \sqrt{a+b x^2}} \, dx}{3 a^4 b^2}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}-\frac{\int \frac{-16 a^3 b^2 B+15 a^2 A b^3 x}{x^2 \sqrt{a+b x^2}} \, dx}{6 a^5 b^2}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}-\frac{(5 A b) \int \frac{1}{x \sqrt{a+b x^2}} \, dx}{2 a^3}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}-\frac{(5 A b) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,x^2\right )}{4 a^3}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}-\frac{(5 A) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b x^2}\right )}{2 a^3}\\ &=\frac{A+B x}{3 a x^2 \left (a+b x^2\right )^{3/2}}+\frac{5 A+4 B x}{3 a^2 x^2 \sqrt{a+b x^2}}-\frac{5 A \sqrt{a+b x^2}}{2 a^3 x^2}-\frac{8 B \sqrt{a+b x^2}}{3 a^3 x}+\frac{5 A b \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )}{2 a^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.148715, size = 106, normalized size = 0.82 \[ \frac{-4 a^2 b (5 A+6 B x)-\frac{3 a^3 (A+2 B x)}{x^2}-a b^2 x^2 (15 A+16 B x)+\frac{15 A b \left (a+b x^2\right )^2 \tanh ^{-1}\left (\sqrt{\frac{b x^2}{a}+1}\right )}{\sqrt{\frac{b x^2}{a}+1}}}{6 a^4 \left (a+b x^2\right )^{3/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.008, size = 134, normalized size = 1. \begin{align*} -{\frac{A}{2\,a{x}^{2}} \left ( b{x}^{2}+a \right ) ^{-{\frac{3}{2}}}}-{\frac{5\,Ab}{6\,{a}^{2}} \left ( b{x}^{2}+a \right ) ^{-{\frac{3}{2}}}}-{\frac{5\,Ab}{2\,{a}^{3}}{\frac{1}{\sqrt{b{x}^{2}+a}}}}+{\frac{5\,Ab}{2}\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{7}{2}}}}-{\frac{B}{ax} \left ( b{x}^{2}+a \right ) ^{-{\frac{3}{2}}}}-{\frac{4\,bBx}{3\,{a}^{2}} \left ( b{x}^{2}+a \right ) ^{-{\frac{3}{2}}}}-{\frac{8\,bBx}{3\,{a}^{3}}{\frac{1}{\sqrt{b{x}^{2}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.69019, size = 683, normalized size = 5.29 \begin{align*} \left [\frac{15 \,{\left (A b^{3} x^{6} + 2 \, A a b^{2} x^{4} + A a^{2} b x^{2}\right )} \sqrt{a} \log \left (-\frac{b x^{2} + 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) - 2 \,{\left (16 \, B a b^{2} x^{5} + 15 \, A a b^{2} x^{4} + 24 \, B a^{2} b x^{3} + 20 \, A a^{2} b x^{2} + 6 \, B a^{3} x + 3 \, A a^{3}\right )} \sqrt{b x^{2} + a}}{12 \,{\left (a^{4} b^{2} x^{6} + 2 \, a^{5} b x^{4} + a^{6} x^{2}\right )}}, -\frac{15 \,{\left (A b^{3} x^{6} + 2 \, A a b^{2} x^{4} + A a^{2} b x^{2}\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{-a}}{\sqrt{b x^{2} + a}}\right ) +{\left (16 \, B a b^{2} x^{5} + 15 \, A a b^{2} x^{4} + 24 \, B a^{2} b x^{3} + 20 \, A a^{2} b x^{2} + 6 \, B a^{3} x + 3 \, A a^{3}\right )} \sqrt{b x^{2} + a}}{6 \,{\left (a^{4} b^{2} x^{6} + 2 \, a^{5} b x^{4} + a^{6} x^{2}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 35.2767, size = 1034, normalized size = 8.02 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24502, size = 266, normalized size = 2.06 \begin{align*} -\frac{{\left ({\left (\frac{5 \, B b^{2} x}{a^{3}} + \frac{6 \, A b^{2}}{a^{3}}\right )} x + \frac{6 \, B b}{a^{2}}\right )} x + \frac{7 \, A b}{a^{2}}}{3 \,{\left (b x^{2} + a\right )}^{\frac{3}{2}}} - \frac{5 \, A b \arctan \left (-\frac{\sqrt{b} x - \sqrt{b x^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a} a^{3}} + \frac{{\left (\sqrt{b} x - \sqrt{b x^{2} + a}\right )}^{3} A b + 2 \,{\left (\sqrt{b} x - \sqrt{b x^{2} + a}\right )}^{2} B a \sqrt{b} +{\left (\sqrt{b} x - \sqrt{b x^{2} + a}\right )} A a b - 2 \, B a^{2} \sqrt{b}}{{\left ({\left (\sqrt{b} x - \sqrt{b x^{2} + a}\right )}^{2} - a\right )}^{2} a^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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